somewhere near the beginning.

Product sigma algebras

Filed under: Mathematics — Alex @ 11:17 pm 9/26/2008

According to Folland’s book, the product sigma algebra \otimes_{\alpha \in A} \mathcal{M}_\alpha of the product space X = \prod_{\alpha \in A} X_\alpha of measurable spaces (X_\alpha, \mathcal{M}_\alpha)_{\alpha \in A} is the smallest sigma algebra for which all the coordinate projections \pi_\alpha : \prod_{\alpha \in A} X_\alpha \rightarrow X_\alpha are measurable. That is, it is the sigma algebra generated by the sets \{ \pi_\alpha^{-1}(E)\,:\, E \in X_\alpha \text{ for some } \alpha \in A\}. According to PlanetMath’s entry, it is the sigma algebra generated by the sets \prod_{\alpha \in A} E_\alpha where E_\alpha = X_\alpha for all but finitely many \alpha.

It’s easy to see these definitions coincide when A is countable– in this case, \otimes_{\alpha \in A} \mathcal{M}_\alpha is the sigma algebra generated by all products of the form \prod_{\alpha \in A} E_\alpha where E_\alpha \in \mathcal{M}_\alpha, but what if A is uncountable? It seems reasonable to expect that they would coincide, specifically, that \otimes_{\alpha \in A} \mathcal{M}_\alpha is the sigma algebra generated by all products of the form \prod_{\alpha \in A} E_\alpha where E_\alpha \in \mathcal{M}_\alpha and E_\alpha = X_\alpha for all but countably many \alpha.

Any ideas on a proof? Duh, never mind. Don’t you hate it when you ask a question you think is nontrivial if not actually hard, then you realize that you spoke too soon?

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