Spectral spread of Graphs

Nikiforov’s July 2010 arXiv paper on the application of Ky Fan norms to graphs poses, among others, the following question: what is the maximal spectral spread of a simple graph of order n?

Here when we refer to the spectrum of a graph, we mean the spectrum of the adjacency matrix of that graph, so we are interested in finding

 \displaystyle
\chi(n) = \max_{|v(G)| = n} \mu_1(G) - \mu_n(G).

The adjacency matrix of a graph is symmetric, so its singular values are simply the absolute values of its eigenvalues. Recall that the Ky Fan k-norm of a matrix is the sum of its top k singular values; it follows that the Ky Fan k-norm of a graph is the sum of the largest k moduli of its eigenvalues. In particular, the Ky Fan two-norm of a graph is given by

 \displaystyle
\|G\|_{(2)} = \max\{\mu_1(G) + |\mu_2(G)|, \mu_1(G) + |\mu_n(G)| \}.

The paper shows that in fact, if n is sufficiently large, then in the graph which achieves \chi(n), |\mu_n(G)| > |\mu_2(G)| so that \|G\|_{(2)} = \mu_1(G) - \mu_n(G) , and the spectral spread of the graph is given by the Ky-fan two norm. So whatever we know about Ky Fan norms can be used.

Here’s a possible avenue towards answering this question, almost entirely due to the observations of one of my colleagues. First, it turns out that the Ky Fan k-norm is the infimal convolution of the trace norm (aka the Ky Fan n-norm) and a scaled spectral norm (aka the Ky Fan 1-norm):


\displaystyle
\|A\|_{(k)} = \inf \{ \|U\|_{(n)} + k \|V\|_{(1)} \,:\, A = U + V \}.

Some results on infimal convolutions  f = \|\cdot\|_1 \diamond \|\cdot\|_2 of norms:

  1. f is a norm
  2. \displaystyle f^\star = \|\cdot\|_1^\star + \|\cdot\|_2^\star = I_{B_{\|\cdot\|_1^\star}} + I_{B_{\|\cdot\|_2^\star}} = I_{B_{\|\cdot\|_1^\star} \cap B_{\|\cdot\|_2^\star}}
  3. where I_A(x) = \begin{cases} 0 & x \in A \\ \infty & x \not\in A \end{cases} is the convex indicator function of a set.

which imply that the unit ball of the norm (trace) dual to f is B_{\|\cdot\|_1^\star} \cap B_{\|\cdot\|_2^\star}. The spectral and trace norms are trace dual, so we have


\displaystyle
B_{\|\cdot\|_{(k)}^\star} = B_{\|\cdot\|_{(2)}} \cap \left(k B_{\|\cdot\|_{(n)}}\right).

Pulling these results together, for n sufficiently large,


\displaystyle
\begin{aligned}
\chi(n) & = \max_{|v(G)| = n} \mu_1(G) - \mu_n(G) = \max_{A} \|A\|_{(2)} = \max_{A} \max_{D \in B_{\|\cdot\|_{(2)}^\star}} \langle A, D \rangle \\
 & = \max_{D \in B_{\|\cdot\|_{(2)}^\star}} \max_A \langle A, D \rangle,
\end{aligned}

where A is in the set of symmetric hollow 0-1 matrices. Since our ambient space is the set of symmetric matrices, the D are also symmetric. It follows that we can achieve the maximum over A by choosing A_{ij} to be 0 zero when D_{ij} is negative, and 1 otherwise. Recalling that A is also hollow, this gives


\displaystyle
\chi(n) = \max_{D \in B_{\|\cdot\|_{(2)}^\star}} \sum_{i\neq j} D_{ij}^{+} = \max_{\{D \,:\, \|D\|_{(1)} \leq 1 \text { and } \|D\|_{(n)} \leq 2\}} \sum_{i \neq j} D_{ij}^+.

This seems like a more geometric reformulation of the problem. Potentially, this bound could let us find lower bounds for \chi(n) by choosing particular choices of D, and could even lead to a direct resolution of the problem.

A side note: if J : X \hookrightarrow Y is the inclusion operator between X, the space of hollow symmetric matrices with the \|\cdot\|_{1 \rightarrow \infty} norm, and Y, the space of symmetric matrices with the Ky Fan 2-norm, then \|J\| \leq 2 \chi(n). I doubt this will ever be a useful observation :)

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